五子棋_C/C++

这只是五子棋的一个排列判定,只能输入坐标两人对仗. 缺少图象函数和鼠标函数; 请指点怎样才能让它选择重玩和鼠标函数的的写法 , 请多多指教!!! #include"stdio.h"
#include"math.h"
#define NUM1 5   /*改变棋盘的宽要大于4*/
#define NUM2 5   /*改变棋盘的长要大于4*/
#define W 27    /*比NUM1*NUM2+1大的数*/
#define V 28    /*比NUM1*NUM2+2大的数 W不能等于V */
main()
{ static int a[NUM1][NUM2],b[NUM1][NUM2],c[NUM1+1][NUM2+1];
                                   /*c数组比a,b大第一横和列作为坐标方便输入*/
int x,y,i,j,m,n,f=1;
    int p=0;
int zuo_biaox=0,zuo_biaoy=0; for(zuo_biaox=1;zuo_biaox<NUM1+1;zuo_biaox=zuo_biaox+1)
      c[0][zuo_biaox]=zuo_biaox-1;
for(zuo_biaoy=1;zuo_biaoy<NUM2+1;zuo_biaoy=zuo_biaoy+1)
      c[zuo_biaoy][0]=zuo_biaoy-1; for(p=0;p<=NUM1*NUM2;p=p+1)
   {int e=1;
    int m1=1,n1=1,t1=0,s1=0,flag1=0,flak1=0,z1=0;
    int m2=1,n2=1,t2=0,s2=0,flag2=0,flak2=0,z2=0;
    int m3=1,n3=1,t3=0,s3=0,flag3=0,flak3=0,z3=0;
    int m4=1,n4=1,t4=0,s4=0,flag4=0,flak4=0,z4=0;
    f=-f;
    if(f<0)
     printf("A: inputx&y:\n");
    if(f>0)
     printf("B: inputx&y:\n");
    scanf("%d %d", &x,&y );
    if((x>=NUM2)(y>=NUM1))    /*坐标不能超过棋盘格数*/
     {f=-f;printf("the number is too big !\n");continue;}
    if(c[y+1][x+1]!=0)              /*已下棋的坐标不能再输入*/
     {f=-f;printf("you can not put here!\n");continue;}
      i=x;
      j=y;
     if(f<0){c[j+1][i+1]=1,c[0][0]=1;}
     if(f>0){c[j+1][i+1]=2,c[0][0]=2;}

     if(f<0)                    /*判定a 数组*/
      {a[j][i]=1;
       for(e=1 ;e<=4;e=e+1)
       {switch(e)
        {case 1:               /*判定前后数值是否与自己相同*/
                 while ((m1<=5)&&(flag1==0))
                 {if(a[j][i+m1]/1==1)
                  {m1=m1+1, t1=t1+1,printf("t1=%d \n",t1);}
                  else flag1=1;
                 }

                  while ((n1<=5)&&(flak1==0))
                  {if(a[j][i-n1]/1==1)
                   {n1=n1+1,s1=s1+1,printf(" s1=%d \n",s1);}
                   else flak1=1;
                 }
                  z1=s1+t1+1;
                  if(z1>=5) {p=W ;e=10;}
                  break;

          case 2:              /*判定上下数值是否与自己相同*/
                  while ((m1<=5)&&(flag2==0))
                  {if(a[j+m2][i]/1==1)
                   {m2=m2+1, t2=t2+1,printf("t2=%d \n",t2);}
                   else flag2=1;
                  }

                   while ((n2<=5)&&(flak2==0))
                   {if(a[j-n2][i]/1==1)
                    {n2=n2+1,s2=s2+1,printf(" s2=%d \n",s2);}
                     else flak2=1;
                  }
                    z2=s2+t2+1;
                    if(z2>=5) {p=W ;e=10;}
                    break;

           case 3:              /*判定右倾斜数值是否与自己相同*/
                    while ((m3<=5)&&(flag3==0))
                    {if(a[j-m3][i+m3]/1==1)
                     {m3=m3+1, t3=t3+1,printf("t3=%d \n",t3);}
                     else flag3=1;
                    }

        &nbs